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  1. The value of (sec245° – cot245°) – (sin230° + sin260°) is
    1. 1
    2. 2√3
    3. 0
    4. 1
      2
Correct Option: C

sec245° – cot245° – sin230° – sin260° = (√2)2 - 1 -
1
2 -
1
2
22

sec245° – cot245° – sin230° – sin260° = 2 - 1 -
1
-
3
44

sec245° – cot245° – sin230° – sin260° = 1 -
1
-
3
44

sec245° – cot245° – sin230° – sin260° =
3
-
3
= 0
44



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