-
The value of (sec245° – cot245°) – (sin230° + sin260°) is
-
- 1
- 2√3
- 0
-
1 √2
- 1
Correct Option: C
sec245° – cot245° – sin230° – sin260° = (√2)2 - 1 - | 2 | - | 2 | ||||||
2 | 2 |
sec245° – cot245° – sin230° – sin260° = 2 - 1 - | - | ||
4 | 4 |
sec245° – cot245° – sin230° – sin260° = 1 - | - | ||
4 | 4 |
sec245° – cot245° – sin230° – sin260° = | - | = 0 | ||
4 | 4 |