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  1. If √2 tan2θ = √6 and 0° < θ < 45°, then the value of sinθ + √3cosθ – 2tan2θ is
    1. 2
      3
    2. 4
      3
    3. 2
    4. 8
      3
Correct Option: B

2 tan2θ = √6

⇒  tan2θ =
6
= √3
2

⇒  tan2θ = tan 60°
⇒  2θ = 60° ⇒ θ = 30°
∴  sinθ + √3 cosθ – 2 tan2θ
= sin 30° + √3 cos 30° – 2 tan230°
=
1
+ √3 ×
3
– 2
1
2
223

=
1
+
3
2
223

=
3 + 9 − 4
=
8
=
4
663



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