If x2 = y + z, y2 = z + x, z2 = x + y, then the

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If x² = y + z, y² = z + x, z² = x + y,
then the value of 1 + 1 + 1 is;
x + 1 x + 1 z + 1

1. –1
2. 1
3. 2
4. 4

Correct Option: B

Tricky Approach
x² = y + z
⇒ x² + x = x + y + z
⇒ x (x + 1) = x + y + z ....(i)
Similarly,
y (y + 1) = x + y + z .........(ii)
and, z (z + 1) = x + y + z ...(iii)

∴	1	+	1	+	1
	x + 1		x + 1		z + 1

=	x	+	y	+	z
	x + y + z		x + y + z		z + y + z

⇒	x + y + z	= 1
	x + y + z

then the value of	1	+	1	+	1	is;
	x + 1		x + 1		z + 1