(ad – bc)2 + (ac + bd)2= a2d2 + b2c2 – 2abcd + a2c2 + b2d2 + 2abcd= a2d2 + b2c2 + a2c2 + b2d2= a2d2 + b2d2 + b2c2 + a2c2= d2(a2 + b2) + c2(b2 + a2)= (a2 + b2) (c2 + d2)= 2 × 1 = 2
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