a2 + b2 + c2 + 3= 2a + 2b + 2c⇒ a2 – 2a + 1 + b2 – 2b + 1 + c2 – 2c + 1 = 0⇒ (a – 1)2 +(b –1)2 +(c – 1)2 = 0⇒ a – 1 = 0 ⇒ a = 1; b – 1 = 0 ⇒ b = 1and, c – 1 = 0 ⇒ c = 1∴ a + b + c = 3
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