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  1. = x2 + y2 +
    1
    +
    1
    = 4, then the value of x2 + y2 is
    x2y2
    1. 2
    2. 4
    3. 8
    4. 16
Correct Option: A

x2 + y2 +
1
+
1
− 4 = 0
x2y2

⇒  x2 +
1
− 2 + y2 +
1
− 2 = 0
x2y2

⇒ x −
1
2 + y −
1
2 = 0
xy

⇒  x −
1
= 0
x

⇒  x2 − 1 = 0 ⇒ x = 1
Similarly,
y = 1
∴  x2 + y2 = 1 + 1 = 2



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