If (2 + √3) = b (2 – √3)b = 1, then

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(2 + √3)a = (2 – √3)b = 1

⇒ a =	1
	2 + √3

∴	1	= 2 + √3
	a

Similarly,

b =	1
	2 − √3

1	= 2 − √3
b

∴	1	+	1	= 2 + √3 + 2 − √3 = 4
	a		b