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If for a non–zero x, 3x2 + 5x + 3 = 0, then the value of x3 + 1 is : x3
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10 27 -
− 10 27 -
2 3 -
− 2 3
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Correct Option: A
3x2 + 5x + 3 = 0
⇒ 3x2 + 3 = –5x
⇒ | = –5 | |
x |
⇒ 3x + | = –5 | |
x |
⇒ x + | = – | ||
x | 3 |
On cubing both sides,
![]() | x + | ![]() | 3 | = | ![]() | ![]() | 3 | = | |||
x | 3 | 27 |
⇒ x3 + | + 3 | ![]() | x + | ![]() | = | |||
x3 | x | 27 |
⇒ x3 + | + 3 × | = | |||
x3 | 3 | 27 |
⇒ x3 + | = | + 5 | ||
x3 | 27 |
= | = | ||
27 | 27 |