a + b + c = 1ab + bc + ca = –1(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca)⇒ 1 = a2 + b2 + c2 + 2 (–1)⇒ a2 + b2 + c2 = 3∴ a3 + b3 + c3 = 3abc + 4= –3 + 4 = 1
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