If p3 – q3 = (p – q) {(p – q)2 + x p q)} then value

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a³ − b³ = (a – b) (a² + ab + b²)
= (a – b) ((a + b)² – ab)
∴ On comparing with
p³ – q³ = (p – q) ((p – q)² + x pq) x
= 3