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If a2 = by + cz, b2 = cz + ax, c2 = ax + by, then the value of
x + y + z is a + x b + y c + z
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- 1
- a + b + c
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1 + 1 + 1 a b c - 0
Correct Option: A
a2 = by + cz
⇒ a2 + ax = ax + by + cz
⇒ a (a + x) = ax + by + cz
| ⇒ | = | ||
| a + x | ax + by + cz |
Similarly,
b2 = cz + ax
⇒ b2 + by = by + cz + ax
⇒ b (b + y) = ax + by + cz
| ⇒ | = | ||
| b + y | ax + by + cz |
c2 = ax + by
⇒ c2 + cz = ax + by + cz
⇒ c (c + z) = ax + by + cz
| ⇒ | = | ||
| c + z | ax + by + cz |
| = | + | + | |||
| ax + by + cz | ax + by + cz | ax + by + cz |
| = | = 1 | |
| ax + by + cz |
