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If a = 299, b = 298, c = 297 then the value of 2a3 + 2b3 + 2c3 – 6abc is
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- 5154
- 5267
- 5364
- 5456
Correct Option: C
2a3 + 2b3 + 2c3 – 6abc
= 2 (a3 + b3 + c3 – 3abc)
| = 2 (a + b + c) × | {(a – b)2 + (b – c)2 + (c – a)2} | |
| 2 |
= (299 + 298 + 297) {(299 – 298)2 + (298 – 297)2 + (297 – 299)2}
= 894 × (1 + 1 + 4)
= 894 × 6 = 5364
