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					 One flies a kite with a thread 150 metre long. If the thread of the kite makes an angle of 60° with the horizontal line, then the height of the kite from the ground (assuming the thread to be in a straight line) is
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                        - 50 metre
- 75 √3 metre
- 25 √3 metre
- 80 metre
 
Correct Option: B
AB = Length of the thread = 150 metre
∆ BAC = 60°
In ∆ ABC,
| sin 60° = | ⇒ | = | ||||
| AB | 2 | 150 | 
| ⇒ BC = 150 × | = 75√3 metre | 2 | 
 
	