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Two posts are x metres apart and the height of one is double that of the other. If from the mid-point of the line joining their feet, an observer finds the angular elevations of their tops to be complementary, then the height (in metres) of the shorter post is
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x 2 √2 -
x 4 - x √2
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x √2
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Correct Option: A
CD = h metre, AB = 2h metre
OB = OD = | metre | 2 |
From ∆OCD,
tan θ = | = | ..........(i) | ||
x | ||||
2 |
From ∆OAB,
tan (90° – θ) = | BO |
⇒ cotθ = | = | ..........(ii) | ||
x | ||||
2 |
Multiplying both equations,
tanθ .cotθ = | × | |||
x | x |
⇒ x2 = 8h2
[∵ tanθcotθ = 1]
⇒ h2 = | 8 |
⇒ h = | metre | 2√2 |