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  1. The value of =
    cos(π + x) cos( -x)
    sin(π - x)cos
    1 - cosB
    2
    1. tan²x
    2. cos²x
    3. cot²x
    4. sec²x
Correct Option: C

=
cos(π + x) cos( -x)
sin(π - x)cos
1 - cosB
2

=
- cosx .cos x
sinx(- sinx)

∵ cos(π + θ) = – cosθ
cos(– θ) = cosθ
sin(π – θ) = – sinθ
=
cos x
 ×
cos x
sinxsinx

= cot x × cotx
= cot²x.


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