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  1. The value of =
    sin 50°
    +
    cos70°
    -2tan² 225° is equal to
    sin 130°cos 110°

    1. 1
    2. –2
    3. 2
    4. 0
Correct Option: B

=
sin 50°
+
cos70°
-2tan² 225°
sin 130°cos 110°

=
sin 50°
+
cos70°
- 2[tan (180° - 45°)]²
sin (180° - 50°)cos (180° - 70°)

=
sin 50°
+
cos 70°
-2tan² 45°
sin 50°)- cos 70°)

∵ sin(180° – θ) = sinθ
cos(180° – θ) = – cosθ
tan(180° + θ) = tanθ
= 1 – 1 – 2 = –2



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