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Let G be the centroid of the equilateral triangle ABC of perimeter 24 cm. Then the length of AG is
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- 2√3cm
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8 cm √3 - 8√3cm
- 4√3cm
Correct Option: B
We draw a figure ,
Let G be the centroid of the equilateral triangle ABC of perimeter 24 cm , 
| AB = BC = CA = | = 8 cm. | |
| 3 |
BD = DC = 4 cm.; AD ⊥ BC
In ∆ABD,
AD = √AB² - BD²
AD = √8² - 4²
AD = √64 - 16
AD = √48 = 4√3cm.
| ∴ AG = | AD = | × 4√3 | ||
| 3 | 3 |
| Hence , the length of AG = | cm. | |
| √3 |
