O is the orthocentre of ∆ABC, and if ∠ BOC = 110°, then ∠ BAC will be
110°
70°
100°
90°
Correct Option: B
Firstly , we draw a figure of triangle ABC whose Point O is the orthocentre , From figure , ∴ ∠ BOC = 180° – ang; A ∴ 110° = 180° – ∠A ( ∴ ∠ BOC = 110° ) ⇒ ∠ A = 180° – 110° = 70°