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∆ABC is an isosceles triangle and AB = AC = 2a unit, BC = a unit. Draw AD⊥ BC , and find the length of AD .
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- √15 a unit
- √15 / 2 a unit
- √17 a unit
- √17 / 2 a unit
Correct Option: B
As per the given in question , we draw a figure of an isosceles triangle ABC
AB = AC = 2a units
BC = a units
| BD = DC = | units | |
| 2 |
AD = √AB² - BD²
| AD = √ | 4a² - | = √ | ||
| 4 | 4 |
| AD = | a units | |
| 2 |
