In ∆ABC, AD is the internal bisector of ∠A, meeting

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In ∆ABC, AD is the internal bisector of ∠A, meeting the side BC at D. If BD = 5 cm, BC = 7.5 cm, then AB : AC is

1. 2 : 1
2. 1 : 2
3. 4 : 5
4. 3 : 5

Correct Option: A

As per the given in question , we draw a figure of a triangle ABC in which AD is the internal bisector of ∠A, meeting the side BC at D ,

AD is the internal bisector of ∠A.
Here , BD = 5 cm, BC = 7.5 cm

∴	AB	=	BD	=	5
	AC		DC		7.5 - 5

AB : AC =	5	= 2 : 1
	2.5