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In a triangle ABC, the side BC is extended up to D. Such that CD = AC, if ∠BAD = 109° and ∠ACB = 72° then the value of ∠ABC is
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- 35°
- 60°
- 40°
- 45°
- 35°
Correct Option: A
On the basis of given in question , we draw a figure triangle ABC ,
∠ACD = 180° – ∠ACB (Linear Pair)
∠ACD = 180° – 72° = 108°
| ∠CAD = ∠ADC = | = 36 cm | 2 |
∴ ∠ABC = 180° – 109° – 36° = 35°
