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  1. If O is the in-centre of ∆ABC; if ∠BOC = 120°, then the measure of ∠BAC is
    1. 30°
    2. 60°
    3. 150°
    4. 75°
Correct Option: B

On the basis of given in question , we draw a figure triangle ABC ,

BO, CO and AO are internal bisectors of ∠B, ∠C and ∠A respectively.
Here , ∠BOC = 120°

∴ ∠BOC = 90° +
∠A
2

⇒ 120° = 90° +
∠A
2

∠A
= 120° - 90° = 30°
2

∴ ∠A = 30 × 2 = 60°



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