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AD is the median of ∆ ABC. If O is the centroid and AO = 10 cm, then OD is
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- 5 cm
- 20 cm
- 10 cm
- 30 cm
- 5 cm
Correct Option: A
We draw a figure triangle ABC whose the side AD is the median and O is the centroid ,
Here , AO = 10 cm
Point O, is the centroid of ∆ ABC.
AO : OD = 2 : 1
⇒ | = | ⇒ 2 × OD = 10 | ||
OD | 1 |
⇒ OD = | = 5 cm. | |
2 |