Correct Option: B

We draw a figure triangle ABC whose the medians BD, CE and AFmeet at point G ,

Point G is the centroid of ∆ ABC.
Point G divides AF (each median) in the ratio 2 : 1.
Proof :-

Reflect ∆ ABC on side AC.
ABCB₁ is a parallelogram.
BEB₁ is a straight line. and
∵ CD = AD, and CD || AD₁
DCD₁A is a parallelogram.
DG || CG₁
∵ BD = DC and DG || CG, and BG = GG₁
∴ BG : GG₁ = 1 : 1
∵ GE = EG₁, BG = GE = 2 : 1