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In ∆ABC, DE || BC such that AD = 3 . If AC = 5.6 cm., then AE is equal to BD 5
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- 4.2 cm.
- 3.1 cm.
- 2.8 cm.
- 2.1 cm.
- 4.2 cm.
Correct Option: D
According to question , we draw a figure ∆ABC 
| Given that , | = | |||
| BD | 5 |
DE||BC
∴ ∠ADE = ∠ABC
∠AED = ∠ACB
By AA – similarity,
∆ADE ≅ ∆ABC
| = | |||
| AD | AE |
| ⇒ | - 1 = | - 1 | ||
| AD | AE |
| ⇒ | = | ||
| AD | AE |
| ⇒ | = | ||
| AD | AE |
| ⇒ | = | ||
| 3 | AE |
⇒ 5AE = 16.8 – 3AE
⇒ 5AE + 3AE = 16.8
⇒ 8AE = 16.8
| ⇒ AE = | = 2.1 cm. | |
| 8 |
