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In a triangle PQR, PQ = PR and ∠Q is twice that of ∠P. Then ∠Q is equal to
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- 72°
- 36°
- 144°
- 108°
- 72°
Correct Option: A
On the basis of question we draw a figure of triangle PQR ,
PQ = PR
∴ ∠PQR is an isosceles triangle.
∴ ∠PQR = ∠PRQ and ∠PQR = 2∠QPR
In ∆ PQR,
We know that ,∠P + ∠Q + ∠R = 180°
⇒ | + ∠Q + ∠Q = 180° | |
2 |
⇒ | ∠Q = 180° | |
2 |
∴ ∠Q = | = 72° | |
5 |