In ∆ PQR, L and M are two points on the sides PQ and

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In ∆ PQR, L and M are two points on the sides PQ and PR respectively such that LM is parallel to QR. If PL = 2cm. LQ = 6 cm and PM = 1.5 cm, then MR (in cm) is

According to question , we draw a figure triangle PQR

LM || QR
∴ ∠PLM = ∠PQR
∠PML = ∠PRQ
∴ By AA–similarity theorem,
∆PLM ~ ∆PQR

∴	PL	=	PM	⇒	2	=	1.5
	LQ		MR		6		MR

⇒ 2MR = 1.5 × 6

⇒ MR =	1.5 × 6	= 4.5 cm.
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