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In a right angled ∆ ABC, ∠ABC = 90°; BN is perpendicular to AC, AB = 6 cm, AC = 10 cm. Then AN : NC is
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- 3 : 4
- 9 :16
- 3 : 16
- 1 : 4
- 3 : 4
Correct Option: B
As per the given in question , we draw a figure triangle ABC 
BC = √10² - 6²
BC = √100 - 36
BC = √64 = 8 cm.
| Area of ∆ ABC = | × BC × AB | |
| 2 |
| Area of ∆ ABC = | × 8 × 6 | = 24Sq. cm. | |
| 2 |
| Again, | × AC × BN | = 24 | |
| 2 |
| ⇒ | × 10 × BN | = 24 | |
| 2 |
| ⇒ BN = | |||
| 5 |
∴ NC = √BC² - BN²
| NC = | √ | 64 - | |
| 25 |
| NC = | cm. | |
| 5 |
| AN = 10 - | = | = | |||
| 5 | 5 | 5 |
| ∴ AN : NC = | : | = 9 : 16 | ||
| 5 | 5 |
