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D and E are two points on the sides AC and BC respectively of ∆ ABC such that DE = 18 cm, CE = 5 cm and ∠DEC = 90°. If tan ∠ABC = 3.6, then AC : CD =
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- BC : 2 CE
- 2 CE : BC
- 2 BC : CE
- CE : 2 BC
- BC : 2 CE
Correct Option: C
On the basis of question we draw a figure of triangle ABC , 
∠DEC = 90°
DE = 18 cm
CE = 5 cm
| ∴ tan C = | = | = 3.6 | ||
| CE | 5 |
tan ∠ABC = 3.6
⇒ ∠C = ∠B
∴ AC = AB
∠C + ∠D = 90°
⇒ 2 ∠C + 2 ∠D = 180°
∠C + ∠A + ∠B = 180°
⇒ 2C + ∠A = 180°
∴ ∠A = 2 ∠D
| ∴ | = | ||
| CB | CE |
| ⇒ | = | or 2BC : CE | ||
| CD | CE |
