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  1. In ∆ ABC, AB = BC = k, AC = √2k, then ∆ ABC is a :
    1. Isosceles triangle
    2. Right-angled triangle
    3. Equilateral triangle
    4. Right isosceles triangle
Correct Option: B

According to question ,
AB = BC = k, AC = √2k
Now , AB² + BC² = k² + k² = 2k² = AC²
∴ ∆ ABC is a right angled triangle.


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