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					 ABCD is a cyclic trapezium with AB || DC and AB = diameter of the circle. If ∠CAB = 30°, then ∠ADC is
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                        -  60° 
 
-  120° 
 
-  150° 
 
- 30°
 
-  60° 
Correct Option: B
According to question , we draw a figure of cyclic trapezium ABCD
∠ACB = 90° (Angle of semi-circle) 
∠CAB = 30° 
∴ ∠CBA =  180°– 90° – 30° = 60° 
Again, ∠ADC + ∠ABC = 180° 
∴ ∠ADC = 180° – 60° = 120°
 
	