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ABCD is a cyclic quadrilateral. AB and DC are produced to meet at P. If ∠ADC = 70° and ∠DAB = 60°, then the ∠PBC + ∠PCB is
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- 130°
- 150°
- 155°
- 180°
- 130°
Correct Option: A
According to question , we draw a figure of cyclic quadrilateral ABCD in which AB and DC are produced to meet at P,
∠ADC = 70°
∠ABC = 180° – 70° = 110°
⇒ ∠PBC = 70°
∠BCD = 180° – 60° = 120°
⇒ ∠PCB = 60°
∴ ∠PBC + ∠PCB = 70° + 60° = 130°