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					 ABCD is a cyclic quadrilateral. AB and DC are produced to meet at P. If ∠ADC = 70° and ∠DAB = 60°, then the ∠PBC + ∠PCB is
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                        -  130° 
 
-  150° 
 
-  155° 
 
- 180°
 
-  130° 
Correct Option: A
According to question , we draw a figure of cyclic  quadrilateral ABCD in which AB and DC are produced to meet at P, 
∠ADC = 70° 
∠ABC = 180° – 70° = 110° 
⇒ ∠PBC = 70° 
∠BCD = 180° – 60° = 120° 
⇒ ∠PCB = 60° 
∴ ∠PBC + ∠PCB = 70° + 60° = 130°
 
	