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The diagonals AC and BD of a cyclic quadrilateral ABCD intersect each other at the point P. Then, it is always true that
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- BP . AB = CD . CP
- AP . CP = BP . DP
- AP . BP = CP . DP
- AP . CD = AB . CP
- BP . AB = CD . CP
Correct Option: B
On the basis of question we draw a figure of cyclic quadrilateral ABCD , 
∴ AP . PC = BP. DP
This theorem is true for cyclic quadrilateral ABCD in which diagonals AC and BD intersect each other at the point P .
