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A quadrilateral ABCD circumscribes a circle and AB = 6 cm, CD = 5 cm and AD = 7 cm. The length of side BC is
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- 4 cm
- 5 cm
- 3 cm
- 6 cm
- 4 cm
Correct Option: A
According to question , we draw a figure of quadrilateral ABCD circumscribes a circle
We know tangents drawn to a circle from same external point are equal
⇒ AM = AQ = x (say)
∴ MB = BN = 6 – x, QD = DP = 7 – x,
Let NC = PC = Z
Now let us Consider side DC = 7 – x + z = 5
BC = 6 – x + z = (7 – x + z) – 1
BC = 5 – 1 = 4