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					 A quadrilateral ABCD circumscribes a circle and AB = 6 cm, CD = 5 cm and AD = 7 cm. The length of side BC is
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                        -  4 cm 
 
-  5 cm 
 
-  3 cm 
 
- 6 cm
 
-  4 cm 
Correct Option: A
According to question , we draw a figure of quadrilateral ABCD circumscribes a circle 
We know tangents drawn to a circle from same external point are equal 
⇒ AM = AQ = x (say) 
∴ MB = BN = 6 – x, QD = DP = 7 – x, 
Let NC = PC = Z 
Now let us Consider side DC = 7 – x + z = 5 
BC = 6 – x + z = (7 – x + z) – 1 
BC = 5 – 1 = 4 
 
	