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ABCD is a cyclic quadrilateral of which AB is the diameter. Diagonals AC and BD intersect at E. If ∠DBC = 35°, then ∠AED measures
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- 35°
- 45°
- 55°
- 90°
- 35°
Correct Option: C
According to question , we draw a figure of cyclic quadrilateral ABCD and AB is a diameter , 
The angle in a semi-circle is right angle.
∴ ∠ADB = ∠ACB = 90°
Given that , ∠DBC = 35°
∴ ∠CEB = 90° – 35° = 55°
∴ ∠CEB = ∠AED = 55°
(Opposite angles)
