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Chords AB and CD of a circle intersect at E and are perpendicular to each other. Segments AE, EB and ED are of lengths 2 cm, 6 cm and 3 cm respectively. Then the length of the diameter of the circle (in cm) is
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- √65
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1 √65 2 - 65
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65 2
Correct Option: A
As per the given in question , we draw a figure circle 
Given , AE = 2 cm
EB = 6 cm
ED = 3 cm
∴ AE × EB = DE × EC
| ⇒ EC = | = 4 cm. | |
| 3 |
∴ Diameter = √7² + 4² = √49 + 16 = √65 cm
