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Two circles with centre P and Q intersect at B and C. A, D are points on the circle such that A, C, D are collinear. If ∠APB = 130°, and ∠BQD = x°, then the value of x is
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- 65
- 130
- 195
- 135
- 65
Correct Option: B
As per the given in question , we draw a figure two circles with centre P and Q intersect at B and C , 
Given that , ∠APB = 130°, and ∠BQD = x°,
| ∴ ∠ BCA = | = 65° | |
| 2 |
⇒ ∠BCD = 180° – 65° = 115°
⇒ Ext. ∠BQD = 2 × 115° = 230°
∴ ∠BQD = 360° – 230° = 130°
