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A, B and C are the three points on a circle such that the angles subtended by the chords AB and AC at the centre O are 90° and 110° respectively. ∠BAC is equal to
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- 70°
- 80°
- 90°
- 100°
- 70°
Correct Option: B
According to question , we draw a figure of a circle with centre O , 
[∵ BOC is not a straight line]
From figure , ∠AOB = 90° ; OA = OB = r
∴ ∠BAO = ∠ABO = 45°
∴ ∠AOC = 110° ; OA = OC = r
| ∴ ∠OAC = ∠OCA = | = 35° | |
| 2 |
∴ ∠BAC = 45° + 35° = 80°
