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					 A, B, C, D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 130° and ∠ECD = 20°. ∠BAC is
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                        -  120° 
 
-  90° 
 
-  100° 
 
- 110°
 
-  120° 
Correct Option: D
According to question , we draw a figure of a circle  , 
Given, ∠BEC = 130° and ∠ECD = 20°
⇒ ∠DEC = 180° – 130° = 50° 
∴ ∠EDC = 180° – 50° – 20° = 110° 
∴ ∠BAC = ∠EDC = 110° 
(Angles on the same arc)
 
	