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Two circles with centres A and B of radii 5 cm and 3 cm respectively touch each other internally. If the perpendicular bisector of AB meets the bigger circle in P and Q, then the value of PQ is
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- √6 cm
- 2√6 cm
- 3√6 cm
- 4√6 cm
- √6 cm
Correct Option: D
As per the given in question , we draw a figure of two circles with centres A and B of radii 5 cm and 3 cm respectively touch each other internally , 
In ∆ PBE,
PB = 5 cm
BE = 1 cm
PE = √PB² - BE²
PE = √25 - 1 = √24 = 2√6 cm
∴ PQ = 2PE = 4√6 cm
