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Two parallel chords of a circle of diameter 20 cm are 12 cm and 16 cm long. If the chords are in the same side of the centre, then the distance between them is
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- 28 cm
- 2 cm
- 4 cm
- 8 cm
- 28 cm
Correct Option: B
According to question , we draw a figure of a circle with centre O and in which two parallel chords are AB and CD , 
OA = OC = radius = 10 cm
AB = 16 cm
CD = 12 cm
In ∆ OAE,
∠OEA = 90°
∴ AE = EB = 8 cm
∴ OE = √OA² - AE²
OE = √10² - 8² = √100 - 64
OE = √36 = 6 cm
In ∆ OFC,
∠OFC = 90°
∴ CF = FD = 6 cm
∴ OF = √OC² - OF²
OF = √10² -6²
OF = √100 - 36
OF = √64 = 8 cm
∴ Required distance = EF = OF – OE
Required distance = 8 – 6 = 2 cm
