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If the length of a chord of a circle is equal to that of the radius of the circle, then the angle subtended, in radians, at the centre of the circle by the chord is
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- 1
- π/2
- π/3
- π/4
- 1
Correct Option: C
We draw a figure with the details in question ,
According to the question,
OA = AB = OB
∴ ∆ OAB is an equilateral triangle.
∴ ∠AOB = 60°
∵ 180° = π radian
∴ 60° = | × 60 = | radian | ||
180 | 2 |