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If PA and PB are two tangents to a circle with centre O such that ∠APB = 80°, then, ∠AOP = ?
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- 40°
- 50°
- 60°
- 70°
- 40°
Correct Option: B
According to question , we draw a figure of a circle with centre O
OA ⊥ PA ; OB ⊥ PB : PA = PB
(tangents from the same external point)
∠APB = 80° : OA = OB = radius
∴ ∠APO = | = 40° | |
2 |
∴ ∠AOP = 90° – 40° = 50°.