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					 A and B are the centres of two circles with radii 11 cm and 6 cm respectively. A common tangent touches these circles at P and Q respectively. If AB = 13 cm., then the length of PQ is
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                        -  13 cm. 
 
-  17 cm. 
 
-  8.5 cm. 
 
- 12 cm.
 
-  13 cm. 
Correct Option: D
As per the given in question , we draw a figure of two circles with radii 11 cm and 6 cm respectively
Here , AB = 13 cm. 
PQ = √(AB)² - (r1 - r2)²
PQ = √(13)² - (11 - 6)² 
PQ = √169 -25 = √144 = 12 cm. 
 
	