-
In the figure below, AB is a chord of a circle with centre O. A tangent AT is drawn at point A so that ∠BAT=50°. Then ∠ADB=?
-
- 120°
- 130°
- 140°
- 150°
- 120°
Correct Option: B
As per the given in question ,
∴ Here , ∠BAT = 50°
OA = OB = radii
∠OAT = 90°
∴ ∠OAB = ∠OBA = 90° – 50° = 40°
∴ ∠AOB = 100°
| ∴ ∠AEB = | = 50° | |
| 2 |
ADBE is a cyclic quadrilateral.
∴ ∠ADB = 180° – 50° = 130°
