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The chord AB of a circle of centre O subtends an angle θ with the tangent at A to the circle. Then measure of ∠ABO is :
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- θ
- 90° – θ
- 90° + θ
- 2 (180° – θ)
- θ
Correct Option: B
On the basis of question we draw a figure of a circle with centre O
Tangent ⇒ CAD
OA ⊥ CD
⇒ OAD = 90° ∠BAD = θ = ∠OBA
From ∆AOB ,
∴ ∠OAB = 90° – θ = ∠OBA
