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PT is a tangent to a circle with centre O and radius 6 cm. If PT is 8 cm then length of OP is
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- 10 cm.
- 12 cm.
- 16 cm.
- 9 cm.
- 10 cm.
Correct Option: A
As per the given in question , we draw a figure of circle with centre O and PT is a tangent
Given that , OT = 6 cm. , TP = 8 cm.
∠OTP = 90°
In ∆ OPT,
OP = √OT² + TP² = √6² + 8²
OP = √36 + 64 = 100 = 10 cm.