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If AB = 5 cm, AC = 12 cm and AB ⊥ AC, then the radius of the circumcircle of ∆ ABC is
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- 6.5 cm
- 6 cm
- 5 cm
- 7 cm
- 6.5 cm
Correct Option: A
According to question , we draw a figure of triangle ABC circumscribes a circle with centre O
Here , AB = 5 cm, AC = 12 cm and AB ⊥ AC
BC = Diameter
From ∆ABC ,
∴ BC = √AB² + AC²
BC = √5² + 12² = √25 + 144
BC = √169 = 13 cm
∴ OB = circum-radius = | = | = 6.5 cm | ||
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