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In a circle if PQ is the diameter of the circle and R is on the circumference of the circle such that ∠PQR = 30°, then ∠RPQ = ?
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- 90°
- 60°
- 30°
- 45°
- 90°
Correct Option: B
As per the given in question , we draw a figure of circle in which PQ is the diameter
Angle of a semi–circle is a right angle.
Given , ∠PQR = 30°
∴ ∠PRQ = 90°
In ∆ PQR,
∠RPQ + ∠RQP = 90°
⇒ ∠RPQ + 30° = 90°
⇒ ∠RPQ = 90° – 30° = 60°