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From a point P on a level ground, the angle of elevation to the top of the tower is 30°. If the tower is 100 metre high, the distance of point P from the foot of the tower is (Take √3 = 1.73)
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- 149 metre
- 156 metre
- 173 metre
- 188 metre
Correct Option: C
Let, AB = Height of tower = 100 metre
∆ACB = 30°
In ∆ABC,
| tan30° = | ||
| BC |
| ⇒ | = | ||
| √3 | BC |
⇒ BC = 100√3 metre = (100 × 1.73) metre = 173 metre
